![\"post27pic8\"](\"http:\/\/advancedmathyoungstudents.com\/blog\/wp-content\/uploads\/2014\/12\/post27pic8.png\")
<\/a><\/p>\nIn this diagram, the secant line segment\u00a0is adjacent to the central angle \u03b8.\u00a0 And the tangent line segment is opposite that same angle.<\/p>\n
But what if we want to draw our secants and tangents relative to the central angle 90-\u03b8, the complement?\u00a0 Let’s add those segments to the diagram and call them the cosecant<\/strong><\/em> and the cotangent<\/strong><\/em>.<\/p>\n EXERCISE #1<\/strong><\/p>\n Find similar triangles and then use ratios to establish each of the following:<\/p>\n (If you need help getting started, I did the first two of these for you in the last post.)<\/p>\n EXERCISE #2<\/strong><\/p>\n Find right triangles and then apply the Pythagorean theorem to establish each of the following:<\/p>\n Those two exercises reveal a lot of information all derived from that one diagram.\u00a0 Once again…it’s better with pictures.<\/p>\n","protected":false},"excerpt":{"rendered":" We almost have the whole picture in view. Here’s where we left off: In this diagram, the secant line segment\u00a0is adjacent to the central angle \u03b8.\u00a0 And the tangent line segment is opposite that same angle. But what if we … Continue reading <\/a><\/p>\n<\/a><\/p>\n<\/a><\/p>\n